Calculating rates of reactions (4.6.1.1) — AQA GCSE Chemistry Revision Notes

Revision notes for AQA GCSE Chemistry specification point 4.6.1.1, Calculating rates of reactions.

Calculating Rate of Reaction

The RATE of a reaction tells you how FAST the reaction occurs and can be determined by two factors:

  • The amount of REACTANTS USED UP in a given time.
  • The amount of PRODUCTS FORMED in a given time.

You can find the rate of a reaction by using the following equations:

Rate Equation 1

Rate Equation2

The UNITS of rate of reaction are usually given in:

  • GRAMS PER SECOND (g/s)
  • CENTIMETRES CUBED PER SECOND (cm³/s)
  • MOLES PER SECOND (mol/s)

Here is an example of a calculation:

Example Calculation

 

RATE GRAPHS

Graphs of "reactants used up" or "products formed" can show how the rate changes throughout a reaction. Generally these graphs would look like this:

Rate Graphs

The rate of reaction is represented by the GRADIENT (steepness) of the line.

The STEEPER the line, the FASTER the rate of reaction.

Both graphs are the STEEPEST at the start, showing that the rate is the FASTEST when the reaction first begins.

The GRADIENT DECREASES as the reaction goes on because the reactant particles get USED UP.

When the line becomes FLAT the reaction is COMPLETE.

 

GRADIENTS

You can work out the GRADIENT of a line by dividing the 'change in y' value by the 'change in x' value.

Gradient

Straight Lines

If the line is STRAIGHT, you can pick TWO POINTS and draw a TRIANGLE from them. Then divide the CHANGE IN Y (vertical length) by the CHANGE IN X (horizontal length).

Straight Line 

In this example, the rate would be calculated as 5/7 which gives a rate of 0.71 g/s.

 

Curved Lines

A curved line is one where the GRADIENT CHANGES.

You can work out the rate at a particular time by drawing a TANGENT.

A TANGENT is a line which touches the curve at ONE POINT and has the SAME GRADIENT as that point.

For example, if you wanted to find the rate of reaction after 3s, you would draw your tangent so it touches the curve at 3s.

Tangent 

Now you can find the GRADIENT by drawing a triangle and finding the 'change in y' and the 'change in x'.

Tangent Gradient

Change in y = 14 – 6 = 8

Change in x = 6 – 2 = 4

Gradient = 8/4 = 2 g/s

The rate of the reaction at 3s is 2g/s.

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